-15.75x^2+184x+320=0

Solution for -15.75x^2+184x+320=0 equation:

-15.75x^2+184x+320=0

a = -15.75; b = 184; c = +320;
Δ = b2-4ac
Δ = 1842-4·(-15.75)·320
Δ = 54016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{54016}=\sqrt{256*211}=\sqrt{256}*\sqrt{211}=16\sqrt{211}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(184)-16\sqrt{211}}{2*-15.75}=\frac{-184-16\sqrt{211}}{-31.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(184)+16\sqrt{211}}{2*-15.75}=\frac{-184+16\sqrt{211}}{-31.5}
$